How do I make a .sh file that counts each time you compile? [closed]

Question

I wanted to compile my program and I wanted to know how many times I have compiled it.

How do I make a .sh file to do that? (I'm using mac, is it .sh file?)

Answer 1

It seems odd to be using a .sh script for build automation. There are several other tools (make, ant, maven) which are much better suited to doing builds and tracking build numbers.

Using one of the more industry standard tools for build automation will, in the long run, make for something that is easier to maintain both for yourself and others.

Answer 2

The following script will do just that in a file declared in the "file" variable:

#! /bin/bash


file="/home/SystemNetworks/file.txt"

if ! test -f $file; then echo 0 > $file; fi
echo $(($(cat $file) + 1)) > $file

At the end of it you can add the command to invoke the build for your project.

Answer 3

Store in a file how many times you have compiled.
When you start the script read the value from the file, increment it and write it back. If the file not exists just create it and write 1 in it.

Answer 4

Its quite Simple, Make a counter in the begining of your script and save the last value in a text file. For example :

Read the value first from the file, like counter =cat /tmp/SomeDIR/LOGS.txt rm /tmp/SomeDIR/LOGS.txt

counter=expr $counter + 1 # increament the counter

Store this counter value in a file

echo $counter > /tmp/SomeDIR/LOGS.txt

Answer 5

If you want to store a state variable that remembers how many times an action took place, the best way to do it would be in an external file that is separate from the script file. So you could read and write to this file, every time you ran the program. The basic pseudocode would be as follows:

1. Get External file name via Command line argument/other means
2. Read compile count value
3. If no value exists
   • Write 1 to external file
4. Else
   • Increment Count Value
   • Write value to external file
5. Exit