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There isn't any cool LINQ sugar for creating unions. The Enumerable.Union() method is usually called like this:

var bigList = list1.Union(list2);

The alternative is to call Enumerable.Union() which can be more readable:

var bigList = Enumerable.Union(list1, list2);

However neither of these methods are very stylish (more importantly, readable) when scaling out The following is probably the best method:

var reallyBigList = list1.Union(list2).Union(list3);

Which can result in some messy method chaining. Alternatives need incidental variables:

var list1and2 = list1.Union(list2);
var reallyBigList = list1and2.Union(list3);


var list1and2 = Enumerable.Union(list1, list2);
var reallyBigList = Enumerable.Union(list1and2, list2);

Is there a clean way of setting up these more complex unions? Would an extension like Enumerable.Union(params IEnumerable<T> collections) (used like var reallyBigList = Enumerable.Union(list1, list2, list3)) be better?

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closed as primarily opinion-based by GlenH7, Snowman, Bart van Ingen Schenau, durron597, MetaFight Sep 16 '15 at 15:41

Many good questions generate some degree of opinion based on expert experience, but answers to this question will tend to be almost entirely based on opinions, rather than facts, references, or specific expertise.If this question can be reworded to fit the rules in the help center, please edit the question.

I don't consider the method chaining option messy at all. Sure, something like

 var reallyBigList = (from ... where ... select ...).Union(from ... where ... select)...

can easily get unreadable, but, on the other hand,

 var mp3s = from ... where ... select ...
 var videos = from ... where ... select ...
 var alreadyProcessed = from ... where ... select ...

 var toDo = mp3s.Union(videos).Except(alreadyProcessed)

reads quite naturally. So, when using well-named intermediate variables, the method chaining approach is extremely readable.

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The method chaining style is pretty readable, in my opinion. Certainly you could write your own extension method to take many IEnumerable<T>.

Here's an example using iteration. Recursion works too, but I didn't like it as much.

public static IEnumerable<T> MyUnion<T>(
    this IEnumerable<T> original, params IEnumerable<T>[] toUnion)
    var enumerable = original;
    foreach (var other in toUnion)
        enumerable = enumerable.Union(other);

    return enumerable;
share|improve this answer
or you could flatten the toUnion array to factor away the loop - return original.Union(toUnion.SelectMany(x => x)); – MattDavey Feb 14 '13 at 9:31
@MattDavey: Note that joining sets in toUnion and then doing the union has a different performance impact than computing the union in a loop. Which one will be faster depends on the context. – MainMa Feb 14 '13 at 9:36
@MainMa agreed, I didn't make any claims about performance, I was merely pointing out there was a more concise way to write the code. – MattDavey Feb 14 '13 at 10:59
I don't think the call to AsEnumerable() is necessary here. – svick Feb 14 '13 at 11:05

protected by gnat Sep 11 '15 at 16:10

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